Given the data: N2 (g) + O2 (g) → 2 NO(g) H = +180.7 kJ 2NO(g) + O2(g) → 2NO2(g) H = -113.1 kJ 2N2O(g) → 2N2 (g) + O2(g) H = -163.2 kJ Use Hess's law to calculate
3. Given the data:
N2 (g) + O2 (g) → 2 NO(g) H = +180.7 kJ
2NO(g) + O2(g) → 2NO2(g) H = -113.1 kJ
2N2O(g) → 2N2 (g) + O2(g) H = -163.2 kJ
Use Hess's law to calculate H for the reaction: (6 points) N2O(g) + NO2(g) → 3 NO(g)
we have to
the first equation remains as it is
The second equation is reversed and divided by 2
the last equation is divided by 2
thus
N2 (g) + O2 (g) → 2 NO(g) H = +180.7 kJ
NO2(g)------> NO(g) + 1/2O2(g) → H = +56.55 kJ
N2O(g) → N2 (g) + 1/2O2(g) H = -81.6kJ
the final equation is
N2O(g) + NO2(g) → 3 NO(g) (H =+180.7 kJ + +56.55 kJ + -81.6kJ )=155.65kJ
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