At what temperature will 41.6 grams N2exerts a pressure of 1.07 atm in a 20.0 L cylinder?
- 12) At what temperature will 41.6 grams N2exerts a pressure of 1.07 atm in a 20.0 L cylinder?
- ANSWER:
- we use the formula PV=nRT
- where :
- P=1.07atm
- V=20.0L
- R=0.0821Latm/Kmol
- T=
- n=moles
- .....
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