At what temperature will 41.6 grams N2exerts a pressure of 1.07 atm in a 20.0 L cylinder?

  • 12) At what temperature will 41.6 grams N2exerts a pressure of 1.07 atm in a 20.0 L cylinder?
  • ANSWER:
  • we use the formula PV=nRT
  • where :
  • P=1.07atm
  • V=20.0L
  • R=0.0821Latm/Kmol
  • T=
  • n=moles
  • .....

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